What is area 20+x-x^2,x^2-5x,[1,3] ?

The answer to area 20+x-x^2,x^2-5x,[1,3] is 140/3

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area 20+x-x^2,x^2-5x,[1,3]

area

20 + x - x^{2}, x^{2} - 5 x, [1, 3]

\frac{140}{3}

Decimal Notation

46.66666 \dots

Solution steps

Apply the area formula:

\int_{1}^{3} 20 + x - x^{2} - (x^{2} - 5 x) d x

Solve

\int_{1}^{3} 20 + x - x^{2} - (x^{2} - 5 x) d x : \frac{140}{3}

The area is:

= \frac{140}{3}

e^{5 x}, at x = \frac{1}{5} ln (3)

\int (x + 1) ln (x + 1) d x

f (x) = (1 + 9 x^{2}) (x - x^{2})

\int (e^{3 x} + 2)^{2} d x

\int \frac{1}{x + 5 x + 6} d x

What is area 20+x-x^2,x^2-5x,[1,3] ?
The answer to area 20+x-x^2,x^2-5x,[1,3] is 140/3