What is the tangent of f(x)= 5/(sqrt(x-7)),(8,5) ?

The tangent of f(x)= 5/(sqrt(x-7)),(8,5) is y=-5/2 x+25

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tangent of f(x)= 5/(sqrt(x-7)),(8,5)

tangent of

f (x) = \frac{5}{x - 7}, (8, 5)

y = - \frac{5}{2} x + 25

Solution steps

Find the slope of

f (x) = \frac{5}{x - 7} : \frac{df ( x )}{d x} = - \frac{5}{2 ( x - 7 ) ^{\frac{3}{2}}}

Compute the slope of

f (x) = \frac{5}{x - 7}

(8, 5) : m = - \frac{5}{2}

Find the line with slope m=

- \frac{5}{2}

and passing through

(8, 5) : y = - \frac{5}{2} x + 25

y = - \frac{5}{2} x + 25

y = x^{16}

\frac{d y}{d x} = x - 2 y

\frac{x}{x}

\int \frac{e ^{6 x}}{e ^{6 x} + 5} d x

7 \to \infty lim (4)

What is the tangent of f(x)= 5/(sqrt(x-7)),(8,5) ?
The tangent of f(x)= 5/(sqrt(x-7)),(8,5) is y=-5/2 x+25