What is the derivative of y=x^2+3x+5 ?

The derivative of y=x^2+3x+5 is 2x+3

What is the first derivative of y=x^2+3x+5 ?

The first derivative of y=x^2+3x+5 is 2x+3

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derivative of

y = x^{2} + 3 x + 5

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5) = 0

= 2 x + 3 + 0

Simplify

= 2 x + 3

\frac{\partial}{\partial x} (arctan (9 x - 9 y))

\int \frac{9 x ^{2} - 4}{x} d x

\int (2 x + 3)^{- 2} d x

y^{^{'}} + 3 y x^{5} = 0

\frac{d}{d x} (w (\frac{x}{50} - F (w, x)))

What is the derivative of y=x^2+3x+5 ?
The derivative of y=x^2+3x+5 is 2x+3
What is the first derivative of y=x^2+3x+5 ?
The first derivative of y=x^2+3x+5 is 2x+3