What is inverse oflaplace {(-3)/(-s+2)} ?

The answer to inverse oflaplace {(-3)/(-s+2)} is 3e^{2t}

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inverse oflaplace {(-3)/(-s+2)}

inverse laplace

{\frac{- 3}{- s + 2}}

3 e^{2 t}

Solution steps

L^{- 1} {\frac{- 3}{- s + 2}}

= L^{- 1} {3 \cdot \frac{1}{s - 2}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 3 L^{- 1} {\frac{1}{s - 2}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 2}} = e^{2 t}

= 3 e^{2 t}

\frac{d}{d x} (x^{2} y^{^{''}} - 9 x y + 25 y)

\int 5 (tan^{2} (x) + tan^{4} (x)) d x

\int (e^{x} + e^{- x}) d x

\int \frac{x ^{3}}{1 - x ^{4}} d x

x = - 5, x = 1, y = 11 x, y = x^{2} - 12

What is inverse oflaplace {(-3)/(-s+2)} ?
The answer to inverse oflaplace {(-3)/(-s+2)} is 3e^{2t}