What is the derivative of \sqrt[3]{x}-3x ?

The derivative of \sqrt[3]{x}-3x is 1/(3x^{2/3)}-3

What is the first derivative of \sqrt[3]{x}-3x ?

The first derivative of \sqrt[3]{x}-3x is 1/(3x^{2/3)}-3

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derivative of

\frac{1}{3 x ^{\frac{2}{3}}} - 3

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (3 x) = 3

= \frac{1}{3 x ^{\frac{2}{3}}} - 3

\frac{4 x ^{2} + 2 x + 4}{x}

\frac{d y}{d x} = e^{4 x} + 5 y

x \to 0 lim (5 x^{4})

\int_{0}^{1} 7 x x^{2} + 16 d x

\frac{d}{d x} (2 sin (x))

What is the derivative of \sqrt[3]{x}-3x ?
The derivative of \sqrt[3]{x}-3x is 1/(3x^{2/3)}-3
What is the first derivative of \sqrt[3]{x}-3x ?
The first derivative of \sqrt[3]{x}-3x is 1/(3x^{2/3)}-3