What is the limit as x approaches 2 of (4x^2-2x+5)/x ?

The limit as x approaches 2 of (4x^2-2x+5)/x is 17/2

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limit as x approaches 2 of (4x^2-2x+5)/x

x \to 2 lim (\frac{4 x ^{2} - 2 x + 5}{x})

\frac{17}{2}

Decimal Notation

8.5

Solution steps

x \to 2 lim (\frac{4 x ^{2} - 2 x + 5}{x})

Plug in the value

x = 2

= \frac{4 \cdot 2 ^{2} - 2 \cdot 2 + 5}{2}

Simplify

= \frac{17}{2}

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What is the limit as x approaches 2 of (4x^2-2x+5)/x ?
The limit as x approaches 2 of (4x^2-2x+5)/x is 17/2