What is the integral of xcos(9x^2) ?

The integral of xcos(9x^2) is 1/18 sin(9x^2)+C

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integral of xcos(9x^2)

\int x cos (9 x^{2}) d x

\frac{1}{18} sin (9 x^{2}) + C

Solution steps

\int x cos (9 x^{2}) d x

Apply u-substitution

: \int \frac{cos ( u )}{18} d u

= \int \frac{cos ( u )}{18} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{18} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{18} sin (u)

Substitute back

u = 9 x^{2}

= \frac{1}{18} sin (9 x^{2})

Add a constant to the solution

= \frac{1}{18} sin (9 x^{2}) + C

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What is the integral of xcos(9x^2) ?
The integral of xcos(9x^2) is 1/18 sin(9x^2)+C