What is the integral from 1 to 4 of x^{-3/2} ?

The integral from 1 to 4 of x^{-3/2} is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of x^{-3/2}

\int_{1}^{4} x^{- \frac{3}{2}} d x

1

Solution steps

\int_{1}^{4} x^{- \frac{3}{2}} d x

Apply the Power Rule

: [- \frac{2}{x ^{\frac{1}{2}}}]_{1}^{4}

= [- \frac{2}{x ^{\frac{1}{2}}}]_{1}^{4}

Compute the boundaries:

1

= 1

\int_{0}^{4} \frac{5 π y ^{4}}{4} d y

\frac{d y}{d x} + y cos (x) = 3 cos (x)

\int \frac{x cos ( x ^{2} )}{sin ( x ^{2} )} d x

y^{^{''}} + 26 y^{^{'}} + 6 y = 0

\int_{0}^{1} (e^{2 x} - e^{x}) d x

What is the integral from 1 to 4 of x^{-3/2} ?
The integral from 1 to 4 of x^{-3/2} is 1