What is the derivative of-19x^2+4x+22 ?

The derivative of-19x^2+4x+22 is -38x+4

What is the first derivative of-19x^2+4x+22 ?

The first derivative of-19x^2+4x+22 is -38x+4

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\frac{d}{d x} (- 19 x^{2} + 4 x + 22)

- 38 x + 4

Solution steps

\frac{d}{d x} (- 19 x^{2} + 4 x + 22)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (19 x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (22)

\frac{d}{d x} (19 x^{2}) = 38 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (22) = 0

= - 38 x + 4 + 0

Simplify

= - 38 x + 4

g (x) = x^{5} - 2 x

\int \frac{1}{x ^{2} - x + 6} d x

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\int (csc (x))^{2} d x

\int \frac{- 10 x ^{2}}{4 x - x ^{2}} d x

What is the derivative of-19x^2+4x+22 ?
The derivative of-19x^2+4x+22 is -38x+4
What is the first derivative of-19x^2+4x+22 ?
The first derivative of-19x^2+4x+22 is -38x+4