What is the solution for (dy)/(dx)=(cos(20x))/(e^{20y)},y(0)=2 ?

The solution for (dy)/(dx)=(cos(20x))/(e^{20y)},y(0)=2 is y=(ln(sin(20x)+e^{40}))/(20)

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(dy)/(dx)=(cos(20x))/(e^{20y)},y(0)=2

\frac{d y}{d x} = \frac{cos ( 20 x )}{e ^{20 y}}, y (0) = 2

y = \frac{ln ( sin ( 20 x ) + e ^{40} )}{20}

Solution steps

\frac{d y}{d x} = \frac{cos ( 20 x )}{e ^{20 y}}

Solve separable ODE:

y = \frac{ln ( sin ( 20 x ) + e ^{40} )}{20}

y = \frac{ln ( sin ( 20 x ) + e ^{40} )}{20}

\int x^{2} cos (d) x d x

\int \frac{cot ( \frac{x}{2} )}{sin ( x )} d x

f (x) = 8 (4 e^{x} - 26)^{4}

x \to 0 lim ((x - 2)^{5})

\frac{1}{s \cdot ( s + 2 )}

What is the solution for (dy)/(dx)=(cos(20x))/(e^{20y)},y(0)=2 ?
The solution for (dy)/(dx)=(cos(20x))/(e^{20y)},y(0)=2 is y=(ln(sin(20x)+e^{40}))/(20)