What is the limit as x approaches 0+of x^{-(17)/(ln(x))} ?

The limit as x approaches 0+of x^{-(17)/(ln(x))} is 1/(e^{17)}

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limit as x approaches 0+of x^{-(17)/(ln(x))}

x \to 0 + lim (x^{- \frac{17}{l n ( x )}})

\frac{1}{e ^{17}}

Decimal Notation

4.13994 E - 8

Solution steps

x \to 0 + lim (x^{- \frac{17}{l n ( x )}})

Apply exponent rules

= x \to 0 + lim (e^{- \frac{17}{l n ( x )} l n (x)})

e^{- \frac{17}{l n ( x )} l n (x)} = \frac{1}{e ^{17}}

= x \to 0 + lim (\frac{1}{e ^{17}})

x \to a lim c = c

= \frac{1}{e ^{17}}

\frac{d y}{d x} = 3 x (e^{2 y})

\frac{d}{d x} (\frac{3 x + 3}{4 e ^{x}})

\int \frac{2 x + 1}{x + 2} d x

\frac{d y}{d x} = (y + 5) (x - 2)

\frac{d}{d x} (2^{s i n (x)} \cdot t a g (x, t) (x - x^{3}))

What is the limit as x approaches 0+of x^{-(17)/(ln(x))} ?
The limit as x approaches 0+of x^{-(17)/(ln(x))} is 1/(e^{17)}