What is the integral from e^2 to e^5 of (1/x) ?

The integral from e^2 to e^5 of (1/x) is 3

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integral from e^2 to e^5 of (1/x)

\int_{e^{2}}^{e^{5}} (\frac{1}{x}) d x

3

Solution steps

\int_{e^{2}}^{e^{5}} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{e^{2}}^{e^{5}}

Compute the boundaries:

3

= 3

(2, 5), (0, - 9)

\frac{u}{u ^{2} + 5}

\int e^{(- 0.1 x)} d x

\frac{d}{d x} (x^{2} - x + 5)

\int_{- 1}^{1} x^{3} - 3 x^{2} - x + 3 d x

What is the integral from e^2 to e^5 of (1/x) ?
The integral from e^2 to e^5 of (1/x) is 3