What is (\partial)/(\partial x)(y^6sin(2x)) ?

The answer to (\partial)/(\partial x)(y^6sin(2x)) is y^6cos(2x)*2

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(\partial)/(\partial x)(y^6sin(2x))

\frac{\partial}{\partial x} (y^{6} sin (2 x))

y^{6} cos (2 x) \cdot 2

Solution steps

\frac{\partial}{\partial x} (y^{6} sin (2 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{6} \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= y^{6} cos (2 x) \cdot 2

x \to \infty lim (- 3 x)

\frac{d}{d x} (a + \frac{1}{x})

1 - x^{2}, x^{2}

\int_{0}^{1} 4 x^{4} e^{- x} d x

\frac{7 ^{2}}{y} - ln (y) - 1

What is (\partial)/(\partial x)(y^6sin(2x)) ?
The answer to (\partial)/(\partial x)(y^6sin(2x)) is y^6cos(2x)*2