What is the integral from 0 to pi/4 of sec^2(t) ?

The integral from 0 to pi/4 of sec^2(t) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi/4 of sec^2(t)

\int_{0}^{\frac{π}{4}} sec^{2} (t) d t

1

Solution steps

\int_{0}^{\frac{π}{4}} sec^{2} (t) d t

Use the common integral:

\int sec^{2} (t) d t = tan (t)

= [tan (t)]_{0}^{\frac{π}{4}}

Compute the boundaries:

1

= 1

\frac{d y}{d x} = \frac{1 - 2 x}{4 x - x ^{2}}

y + 6 y^{3}

f (x) = \frac{x - x ^{2}}{3 x ^{2} + 2}

\int \frac{3 x ^{2}}{5} + \frac{7 x ^{3}}{8} d x

\int - 10 x^{5} e^{x^{6}} d x

What is the integral from 0 to pi/4 of sec^2(t) ?
The integral from 0 to pi/4 of sec^2(t) is 1