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Popular >

integral of 1+t

Solution

\int 1 + t d t

Solution

t + \frac{t ^{2}}{2} + C

Solution steps

\int 1 + t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d t + \int t d t

\int 1 d t = t

\int t d t = \frac{t ^{2}}{2}

= t + \frac{t ^{2}}{2}

Add a constant to the solution

= t + \frac{t ^{2}}{2} + C

Popular Examples

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\int x^{5} + 8 x^{3} - 9 x^{2} + 7 x - 5 d x

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\int - x^{3} + \frac{1}{x ^{2}} d x

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\int \frac{4 e ^{- \frac{3}{x ^{5}}}}{x ^{6}} d x

Frequently Asked Questions (FAQ)

What is the integral of 1+t ?
The integral of 1+t is t+(t^2)/2+C