What is the derivative of sqrt(x)-1/(\sqrt[4]{x}) ?

The derivative of sqrt(x)-1/(\sqrt[4]{x}) is 1/(2sqrt(x))+1/(4x^{5/4)}

What is the first derivative of sqrt(x)-1/(\sqrt[4]{x}) ?

The first derivative of sqrt(x)-1/(\sqrt[4]{x}) is 1/(2sqrt(x))+1/(4x^{5/4)}

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\frac{1}{2 x} + \frac{1}{4 x ^{\frac{5}{4}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} - (- \frac{1}{4 x ^{\frac{5}{4}}})

Simplify

= \frac{1}{2 x} + \frac{1}{4 x ^{\frac{5}{4}}}

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x y^{^{'}} - y = y^{3}

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What is the derivative of sqrt(x)-1/(\sqrt[4]{x}) ?
The derivative of sqrt(x)-1/(\sqrt[4]{x}) is 1/(2sqrt(x))+1/(4x^{5/4)}
What is the first derivative of sqrt(x)-1/(\sqrt[4]{x}) ?
The first derivative of sqrt(x)-1/(\sqrt[4]{x}) is 1/(2sqrt(x))+1/(4x^{5/4)}