What is the integral of (-3cos(x)+4sec^2(x)) ?

The integral of (-3cos(x)+4sec^2(x)) is -3sin(x)+4tan(x)+C

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integral of (-3cos(x)+4sec^2(x))

\int (- 3 cos (x) + 4 sec^{2} (x)) d x

- 3 sin (x) + 4 tan (x) + C

Solution steps

\int - 3 cos (x) + 4 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 3 cos (x) d x + \int 4 sec^{2} (x) d x

\int 3 cos (x) d x = 3 sin (x)

\int 4 sec^{2} (x) d x = 4 tan (x)

= - 3 sin (x) + 4 tan (x)

Add a constant to the solution

= - 3 sin (x) + 4 tan (x) + C

\frac{d}{d x} (y e^{2 x})

f (x) = \frac{x}{7}

x \to 0 lim (\frac{sin ^{4} ( 2 x )}{4 x ^{4}})

\frac{d v}{d t} = 0.64 - \frac{v}{2940} \cdot 8, v (0) = 0

\int (t^{3} - 3 t) (2 t) d t

What is the integral of (-3cos(x)+4sec^2(x)) ?
The integral of (-3cos(x)+4sec^2(x)) is -3sin(x)+4tan(x)+C