What is the derivative of 2/(7x^4) ?

The derivative of 2/(7x^4) is -8/(7x^5)

What is the first derivative of 2/(7x^4) ?

The first derivative of 2/(7x^4) is -8/(7x^5)

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\frac{d}{d x} (\frac{2}{7 x ^{4}})

- \frac{8}{7 x ^{5}}

Solution steps

\frac{d}{d x} (\frac{2}{7 x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{7} \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{2}{7} \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{7} (- 4 x^{- 4 - 1})

Simplify

\frac{2}{7} (- 4 x^{- 4 - 1}) : - \frac{8}{7 x ^{5}}

= - \frac{8}{7 x ^{5}}

\frac{\partial}{\partial x} (cos (x^{5} + y))

\int 2 x e^{y} d x

f (x) = \frac{( x + 3 ) ( x + 1 )}{x ^{2} - 49}

y = ln (x + x^{2} + 6)

x^{\frac{1}{4}}, 16

What is the derivative of 2/(7x^4) ?
The derivative of 2/(7x^4) is -8/(7x^5)
What is the first derivative of 2/(7x^4) ?
The first derivative of 2/(7x^4) is -8/(7x^5)