What is the derivative of (x+1^3-x^3) ?

The derivative of (x+1^3-x^3) is 6x+3

What is the first derivative of (x+1^3-x^3) ?

The first derivative of (x+1^3-x^3) is 6x+3

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\frac{d}{d x} ((x + 1)^{3} - x^{3})

6 x + 3

Solution steps

\frac{d}{d x} ((x + 1)^{3} - x^{3})

Simplify

(x + 1)^{3} - x^{3} : 3 x^{2} + 3 x + 1

= \frac{d}{d x} (3 x^{2} + 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 6 x + 3 + 0

Simplify

= 6 x + 3

\int_{2}^{4} \frac{2}{x ^{2} - 6 x + 10} d x

(- 2.1) (4.2)

f (x) = (x^{2} + 7) (5 - x), at x = 0

\frac{d}{d x} (x^{4} + (y - 2)^{3})

\int \frac{( x ^{2} - 2 x + 1 ) ^{\frac{1}{5}}}{1 - x} d x

What is the derivative of (x+1^3-x^3) ?
The derivative of (x+1^3-x^3) is 6x+3
What is the first derivative of (x+1^3-x^3) ?
The first derivative of (x+1^3-x^3) is 6x+3