What is the integral of sec(10w)tan(10w) ?

The integral of sec(10w)tan(10w) is 1/10 sec(10w)+C

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integral of sec(10w)tan(10w)

\int sec (10 w) tan (10 w) d w

\frac{1}{10} sec (10 w) + C

Solution steps

\int sec (10 w) tan (10 w) d w

Apply u-substitution

: \int \frac{1}{10} d u

= \int \frac{1}{10} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{10} u

Substitute back

u = sec (10 w)

= \frac{1}{10} sec (10 w)

Add a constant to the solution

= \frac{1}{10} sec (10 w) + C

x \to 0 lim (\frac{x}{x ^{2} - 2 x})

\frac{d}{d x} (\frac{8 x}{5 - cot ( x )})

x \to 7 lim (2 x - ∣ x - 7 ∣)

x \to 0 lim (e^{- 6 x})

f (x) = \frac{1}{y ^{2}}

What is the integral of sec(10w)tan(10w) ?
The integral of sec(10w)tan(10w) is 1/10 sec(10w)+C