What is the solution for x(dy)/(dx)=y+xe^{y/x} ?

The solution for x(dy)/(dx)=y+xe^{y/x} is y=-xln(-ln(x)-c_{1})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x(dy)/(dx)=y+xe^{y/x}

x \frac{d y}{d x} = y + x e^{\frac{y}{x}}

y = - x ln (- ln (x) - c_{1})

Solution steps

x \frac{d y}{d x} = y + x e^{\frac{y}{x}}

Solve using substitution:

y = - x ln (- ln (x) - c_{1})

y = - x ln (- ln (x) - c_{1})

\int_{0}^{\frac{π}{3}} sin^{3} (x) d x

\int (1 - r) r d r

\frac{\partial}{\partial y} (- 2 x)

\int e^{- x} \cdot x d x

\int 6^{s i n (x)} cos (x) d x

What is the solution for x(dy)/(dx)=y+xe^{y/x} ?
The solution for x(dy)/(dx)=y+xe^{y/x} is y=-xln(-ln(x)-c_{1})