What is the solution for (dy)/(dx)=0.15y+200 ?

The solution for (dy)/(dx)=0.15y+200 is y=(e^{0.15x+c_{1}})/(0.15)-(200)/(0.15)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=0.15y+200

\frac{d y}{d x} = 0.15 y + 200

y = \frac{e ^{0.15 x + c_{1}}}{0.15} - \frac{200}{0.15}

Solution steps

\frac{d y}{d x} = 0.15 y + 200

Solve separable ODE:

y = \frac{e ^{0.15 x + c_{1}}}{0.15} - \frac{200}{0.15}

y = \frac{e ^{0.15 x + c_{1}}}{0.15} - \frac{200}{0.15}

(- x)^{^{'}}

\frac{d}{d x} (ln (arcsin (x)))

\int (\frac{- x ^{2} + x}{x ^{4}}) d x

\int 2 x - 2 x^{2} d x

f (x) = x^{2}, g (x) = 2 x

What is the solution for (dy)/(dx)=0.15y+200 ?
The solution for (dy)/(dx)=0.15y+200 is y=(e^{0.15x+c_{1}})/(0.15)-(200)/(0.15)