What is the first derivative of 2(x-pi) ?

The first derivative of 2(x-pi) is 2

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derivative of 2(x-pi)

\frac{d}{d x} (2 (x - π))

2

Solution steps

\frac{d}{d x} (2 (x - π))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x - π)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 2 (\frac{d x}{d x} - \frac{d}{d x} (π))

\frac{d x}{d x} = 1

\frac{d}{d x} (π) = 0

= 2 (1 - 0)

Simplify

= 2

\frac{d}{d x} (a x e^{x})

\frac{\partial}{\partial u} (5 u^{2} + 8 v^{2})

x \to 0 lim (\frac{1 - cos ( x )}{2})

\frac{d}{d x} (π^{5})

y^{^{''''}} - 5 y^{^{''}} + 4 y = 0