What is the derivative of e^x+e^{-2x} ?

The derivative of e^x+e^{-2x} is e^x-2e^{-2x}

What is the first derivative of e^x+e^{-2x} ?

The first derivative of e^x+e^{-2x} is e^x-2e^{-2x}

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\frac{d}{d x} (e^{x} + e^{- 2 x})

e^{x} - 2 e^{- 2 x}

Solution steps

\frac{d}{d x} (e^{x} + e^{- 2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (e^{- 2 x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{- 2 x}) = - 2 e^{- 2 x}

= e^{x} - 2 e^{- 2 x}

\int_{0}^{π} sin (x) d x

y^{^{''}} + y^{^{'}} - 2 y = x^{3} - e^{- x}

\frac{d}{d x} (cos (x) + ln (tan (\frac{x}{2})))

\frac{d}{d y} (ln (x^{2} + y^{2} + z^{2}))

f (x) = ln (2 x + 1)

What is the derivative of e^x+e^{-2x} ?
The derivative of e^x+e^{-2x} is e^x-2e^{-2x}
What is the first derivative of e^x+e^{-2x} ?
The first derivative of e^x+e^{-2x} is e^x-2e^{-2x}