What is the solution for 3y^'-2y=e^{-(pit)/2} ?

The solution for 3y^'-2y=e^{-(pit)/2} is y= 2/((-3pi-4)e^{(pit){2}}}+c_{1}e^{\frac{2t)/3}

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3y^'-2y=e^{-(pit)/2}

3 y^{^{'}} - 2 y = e^{- \frac{π t}{2}}

y = \frac{2}{( - 3 π - 4 ) e ^{\frac{π t}{2}}} + c_{1} e^{\frac{2 t}{3}}

Solution steps

3 y^{'} (t) - 2 y = e^{- \frac{π t}{2}}

Solve linear ODE:

y = \frac{2}{( - 3 π - 4 ) e ^{\frac{π t}{2}}} + c_{1} e^{\frac{2 t}{3}}

y = \frac{2}{( - 3 π - 4 ) e ^{\frac{π t}{2}}} + c_{1} e^{\frac{2 t}{3}}

6 x^{5} e^{x} + e^{x} x^{6}

n = 1 \sum \infty \frac{4}{n ( n + 2 )}

x^{\frac{6}{5}}

y^{^{''}} - 4 y^{^{'}} - 5 y = 9 e^{2 t}

\int - π cos (π) x d x

What is the solution for 3y^'-2y=e^{-(pit)/2} ?
The solution for 3y^'-2y=e^{-(pit)/2} is y= 2/((-3pi-4)e^{(pit){2}}}+c_{1}e^{\frac{2t)/3}