What is the d/(dt)(-asin(t)+bcos(t)) ?

The d/(dt)(-asin(t)+bcos(t)) is -acos(t)-bsin(t)

What is the first d/(dt)(-asin(t)+bcos(t)) ?

The first d/(dt)(-asin(t)+bcos(t)) is -acos(t)-bsin(t)

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\frac{d}{d t} (- a sin (t) + b cos (t))

- a cos (t) - b sin (t)

Solution steps

\frac{d}{d t} (- a sin (t) + b cos (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (a sin (t)) + \frac{d}{d t} (b cos (t))

\frac{d}{d t} (a sin (t)) = a cos (t)

\frac{d}{d t} (b cos (t)) = - b sin (t)

= - a cos (t) - b sin (t)

x \to 0 lim ((tan (8 x))^{x})

\frac{d}{d x} (\frac{3 x}{e ^{x}})

\int \frac{1}{x 9 x ^{2} + 49} d x

\int 12 x e^{- 2 x} d x

\frac{d}{d x} ((sin (3 x))^{3} + 5 x)

What is the d/(dt)(-asin(t)+bcos(t)) ?
The d/(dt)(-asin(t)+bcos(t)) is -acos(t)-bsin(t)
What is the first d/(dt)(-asin(t)+bcos(t)) ?
The first d/(dt)(-asin(t)+bcos(t)) is -acos(t)-bsin(t)