What is laplacetransform cos(2t+pi) ?

The answer to laplacetransform cos(2t+pi) is -s/(s^2+4)

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laplacetransform cos(2t+pi)

laplace transform

cos (2 t + π)

- \frac{s}{s ^{2} + 4}

Solution steps

L {cos (2 t + π)}

Use Laplace Transform table:

L {cos (a t + b)} = \frac{s \cdot cos ( b ) - a \cdot sin ( b )}{s ^{2} + a ^{2}}

L {cos (2 t + π)} = \frac{s cos ( π ) - 2 sin ( π )}{s ^{2} + 2 ^{2}}

= \frac{s cos ( π ) - 2 sin ( π )}{s ^{2} + 2 ^{2}}

= - \frac{s}{s ^{2} + 4}

ln (sec (x) + tan (x))

\frac{d}{d x} (x^{\frac{1}{n}})

x + y e^{\frac{y}{x}} d x - x e^{\frac{y}{x}} d y = 0

\frac{\partial}{\partial u} (a u)

\int \frac{x}{e ^{x^{2} - 8}} d x

What is laplacetransform cos(2t+pi) ?
The answer to laplacetransform cos(2t+pi) is -s/(s^2+4)