What is the solution for 11t^2y^{''}-22y=9t^2-9 ?

The solution for 11t^2y^{''}-22y=9t^2-9 is y=c_{1}t^2+(c_{2})/t+(6t^2ln(t)-2t^2+9)/(22)

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11t^2y^{''}-22y=9t^2-9

11 t^{2} y^{^{''}} - 22 y = 9 t^{2} - 9

y = c_{1} t^{2} + \frac{c _{2}}{t} + \frac{6 t ^{2} ln ( t ) - 2 t ^{2} + 9}{22}

Solution steps

11 t^{2} y^{''} (t) - 22 y = 9 t^{2} - 9

Solve linear ODE:

y = c_{1} t^{2} + \frac{c _{2}}{t} + \frac{6 t ^{2} ln ( t ) - 2 t ^{2} + 9}{22}

y = c_{1} t^{2} + \frac{c _{2}}{t} + \frac{6 t ^{2} ln ( t ) - 2 t ^{2} + 9}{22}

x \to 0 lim (cos (2 - 2 e^{x}))

x \to 1 lim (2)

x \to 6 - lim (tan (\frac{π x}{4}))

\int \frac{1}{x ( x ^{3} + 1 )} d x

y = e^{3 x}, x = 0, x = 3

What is the solution for 11t^2y^{''}-22y=9t^2-9 ?
The solution for 11t^2y^{''}-22y=9t^2-9 is y=c_{1}t^2+(c_{2})/t+(6t^2ln(t)-2t^2+9)/(22)