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Popular >

y^'=2cos(5x)

Solution

y^{^{'}} = 2 cos (5 x)

Solution

y = \frac{2}{5} sin (5 x) + c_{1}

Solution steps

y^{'} (x) = 2 cos (5 x)

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 2 cos (5 x) d x

\int 2 cos (5 x) d x = \frac{2}{5} sin (5 x) + c_{1}

y = \frac{2}{5} sin (5 x) + c_{1}

Popular Examples

y^{''}+3y^'+2y=x^2

y^{^{''}} + 3 y^{^{'}} + 2 y = x^{2}

derivative of (-2/(xsqrt(x)))

\frac{d}{d x} (\frac{- 2}{x x})

derivative of (3x^{1/2})

\frac{d}{d x} ((3 x)^{\frac{1}{2}})

derivative of 14e^{2x}

\frac{d}{d x} (14 e^{2 x})

(cos(6x))y^'-6(tan(6x))y=-2sec(6x)

(cos (6 x)) y^{^{'}} - 6 (tan (6 x)) y = - 2 sec (6 x)

Frequently Asked Questions (FAQ)

What is the solution for y^'=2cos(5x) ?
The solution for y^'=2cos(5x) is y= 2/5 sin(5x)+c_{1}