What is the derivative of 8sin(8x) ?

The derivative of 8sin(8x) is 64cos(8x)

What is the first derivative of 8sin(8x) ?

The first derivative of 8sin(8x) is 64cos(8x)

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\frac{d}{d x} (8 sin (8 x))

64 cos (8 x)

Solution steps

\frac{d}{d x} (8 sin (8 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (sin (8 x))

Apply the chain rule:

cos (8 x) \frac{d}{d x} (8 x)

= cos (8 x) \frac{d}{d x} (8 x)

\frac{d}{d x} (8 x) = 8

= 8 cos (8 x) \cdot 8

Simplify

= 64 cos (8 x)

\frac{d}{d x} (x^{\frac{1}{1}})

f (x) = \frac{x}{x ^{2} + 7}

x \to + 0 + lim (\frac{x ^{2}}{4} - \frac{2}{x})

y^{^{''}} + 6 y^{^{'}} + 9 y = 1 + x

\frac{d}{d x} (I n x^{3})

What is the derivative of 8sin(8x) ?
The derivative of 8sin(8x) is 64cos(8x)
What is the first derivative of 8sin(8x) ?
The first derivative of 8sin(8x) is 64cos(8x)