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Popular >

integral from-1 to 0 of (2x-1)

Solution

\int_{- 1}^{0} (2 x - 1) d x

Solution

- 2

Solution steps

\int_{- 1}^{0} 2 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 2 x d x - \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} 2 x d x = - 1

\int_{- 1}^{0} 1 d x = 1

= - 1 - 1

Simplify

= - 2

Popular Examples

f^{''}(x)=-f(x),f(0)=0,f^'(0)=1

f^{^{''}} (x) = - f (x), f (0) = 0, f^{^{'}} (0) = 1

sum from n=1 to infinity}e^{-6n of-e^{-6(n+1)}

n = 1 \sum \infty e^{- 6 n} - e^{- 6 (n + 1)}

integral of (4x-3)5

\int (4 x - 3) 5 d x

integral from-2 to 6 of 4x-x^2-12

\int_{- 2}^{6} 4 x - x^{2} - 12 d x

derivative of 3x^2e^x+e^x(x^3+7)derivative of

3 x^{2} e^{x} + e^{x} (x^{3} + 7)

Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of (2x-1) ?
The integral from-1 to 0 of (2x-1) is -2