What is laplacetransform e(t+1) ?

The answer to laplacetransform e(t+1) is e/(s^2)+e/s

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform e(t+1)

laplace transform

e (t + 1)

\frac{e}{s ^{2}} + \frac{e}{s}

Solution steps

L {e (t + 1)}

Expand

e (t + 1) : e t + e

= L {e t + e}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= e L {t} + L {e}

L {t} : \frac{1}{s ^{2}}

L {e} : \frac{e}{s}

= e \frac{1}{s ^{2}} + \frac{e}{s}

Refine

e \frac{1}{s ^{2}} + \frac{e}{s} : \frac{e}{s ^{2}} + \frac{e}{s}

= \frac{e}{s ^{2}} + \frac{e}{s}

\frac{\partial}{\partial y} (3 x^{4} e^{y})

\int \frac{24}{( x ^{2} - 9 )} d x

\int \frac{1}{5 - 4 r - r ^{2}} d r

f (x) = \frac{x}{1 + 5 x ^{2}}, at x = 3

y = x + 3

What is laplacetransform e(t+1) ?
The answer to laplacetransform e(t+1) is e/(s^2)+e/s