What is the tangent of y= 2/(sqrt(x)),(36, 2/6) ?

The tangent of y= 2/(sqrt(x)),(36, 2/6) is y=-1/216 x+1/2

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tangent of y= 2/(sqrt(x)),(36, 2/6)

tangent of

y = \frac{2}{x}, (36, \frac{2}{6})

y = - \frac{1}{216} x + \frac{1}{2}

Solution steps

Find the slope of

y = \frac{2}{x} : \frac{d y}{d x} = - \frac{1}{x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{2}{x}

(36, \frac{2}{6}) : m = - \frac{1}{216}

Find the line with slope m=

- \frac{1}{216}

and passing through

(36, \frac{2}{6}) : y = - \frac{1}{216} x + \frac{1}{2}

y = - \frac{1}{216} x + \frac{1}{2}

\frac{d}{d x} (- x + \frac{6}{x} + 1)

\int \frac{2 x + 3}{x ^{3} + x} d x

\int_{- 2}^{2} - x^{2} + 4 d x

\frac{d y}{d x} = 9.8 - 0.2 y

What is the tangent of y= 2/(sqrt(x)),(36, 2/6) ?
The tangent of y= 2/(sqrt(x)),(36, 2/6) is y=-1/216 x+1/2