What is the derivative of y=arctan(2-x) ?

The derivative of y=arctan(2-x) is -1/(x^2-4x+5)

What is the first derivative of y=arctan(2-x) ?

The first derivative of y=arctan(2-x) is -1/(x^2-4x+5)

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derivative of

y = arctan (2 - x)

- \frac{1}{x ^{2} - 4 x + 5}

Solution steps

\frac{d}{d x} (arctan (2 - x))

Apply the chain rule:

\frac{1}{( 2 - x ) ^{2} + 1} \frac{d}{d x} (2 - x)

= \frac{1}{( 2 - x ) ^{2} + 1} \frac{d}{d x} (2 - x)

\frac{d}{d x} (2 - x) = - 1

= \frac{1}{( 2 - x ) ^{2} + 1} (- 1)

Simplify

\frac{1}{( 2 - x ) ^{2} + 1} (- 1) : - \frac{1}{x ^{2} - 4 x + 5}

= - \frac{1}{x ^{2} - 4 x + 5}

(2 + t)^{4}

\frac{d}{d x} (\frac{x \cdot cos ( x ) - 2 π}{x - 2 π})

\int 163 cos^{4} (3 x) sin^{2} (3 x) d x

\int 5^{- 4 (x - 7)} d x

\frac{d}{d x} (\frac{6}{3 x})

What is the derivative of y=arctan(2-x) ?
The derivative of y=arctan(2-x) is -1/(x^2-4x+5)
What is the first derivative of y=arctan(2-x) ?
The first derivative of y=arctan(2-x) is -1/(x^2-4x+5)