What is the derivative of 2e^{3t+2x} ?

The derivative of 2e^{3t+2x} is 6e^{3t+2x}

What is the first derivative of 2e^{3t+2x} ?

The first derivative of 2e^{3t+2x} is 6e^{3t+2x}

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derivative of

2 e^{3 t + 2 x}

6 e^{3 t + 2 x}

Solution steps

\frac{d}{d t} (2 e^{3 t + 2 x})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (e^{3 t + 2 x})

Apply the chain rule:

e^{3 t + 2 x} \frac{d}{d t} (3 t + 2 x)

= e^{3 t + 2 x} \frac{d}{d t} (3 t + 2 x)

\frac{d}{d t} (3 t + 2 x) = 3

= 2 e^{3 t + 2 x} \cdot 3

Simplify

= 6 e^{3 t + 2 x}

\frac{25}{s ( s ^{2} + 4 s + 5 )}

\int 2 sec^{4} (7 x) d x

11 x - 6 sin (x)

\int \frac{3 e ^{x}}{x} d x

\frac{d}{d x} (3 (5 - 9 x)^{5})

What is the derivative of 2e^{3t+2x} ?
The derivative of 2e^{3t+2x} is 6e^{3t+2x}
What is the first derivative of 2e^{3t+2x} ?
The first derivative of 2e^{3t+2x} is 6e^{3t+2x}