What is the derivative of (x^2-4^2) ?

The derivative of (x^2-4^2) is 4x(x^2-4)

What is the first derivative of (x^2-4^2) ?

The first derivative of (x^2-4^2) is 4x(x^2-4)

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\frac{d}{d x} ((x^{2} - 4)^{2})

4 x (x^{2} - 4)

Solution steps

\frac{d}{d x} ((x^{2} - 4)^{2})

Apply the chain rule:

2 (x^{2} - 4) \frac{d}{d x} (x^{2} - 4)

= 2 (x^{2} - 4) \frac{d}{d x} (x^{2} - 4)

\frac{d}{d x} (x^{2} - 4) = 2 x

= 2 (x^{2} - 4) \cdot 2 x

Simplify

= 4 x (x^{2} - 4)

\frac{d y}{d x} = sin (3 x) - cos (5 x)

(3 t - 1) (4 t - 4)^{- 1}

\int x \frac{1}{2} d x

\frac{d}{d x} (2 x - 5)

\frac{\partial}{\partial x} (1 + arctan (x))

What is the derivative of (x^2-4^2) ?
The derivative of (x^2-4^2) is 4x(x^2-4)
What is the first derivative of (x^2-4^2) ?
The first derivative of (x^2-4^2) is 4x(x^2-4)