What is (\partial)/(\partial y)(x^2y^2z^2) ?

The answer to (\partial)/(\partial y)(x^2y^2z^2) is 2x^2yz^2

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(\partial)/(\partial y)(x^2y^2z^2)

\frac{\partial}{\partial y} (x^{2} y^{2} z^{2})

2 x^{2} y z^{2}

Solution steps

\frac{\partial}{\partial y} (x^{2} y^{2} z^{2})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} z^{2} \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x^{2} z^{2} \cdot 2 y^{2 - 1}

Simplify

= 2 x^{2} y z^{2}

\int \frac{ln ( x )}{x ( ln ^{2} ( x ) + 4 )} d x

y^{^{''}} + 36 y = 12 sin (6 t)

\frac{d y}{d x} = \frac{x - 3}{y - 3}

\int \frac{1}{4 x + 5 x} d x

\frac{\partial}{\partial y} (2 cos (x))

What is (\partial)/(\partial y)(x^2y^2z^2) ?
The answer to (\partial)/(\partial y)(x^2y^2z^2) is 2x^2yz^2