What is the integral of 1-x^2-3x^5 ?

The integral of 1-x^2-3x^5 is x-(x^3)/3-(x^6)/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1-x^2-3x^5

\int 1 - x^{2} - 3 x^{5} d x

x - \frac{x ^{3}}{3} - \frac{x ^{6}}{2} + C

Solution steps

\int 1 - x^{2} - 3 x^{5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x - \int x^{2} d x - \int 3 x^{5} d x

\int 1 d x = x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 3 x^{5} d x = \frac{x ^{6}}{2}

= x - \frac{x ^{3}}{3} - \frac{x ^{6}}{2}

Add a constant to the solution

= x - \frac{x ^{3}}{3} - \frac{x ^{6}}{2} + C

x^{2} - 5 x

\frac{5 s}{( s + 7 ) ( s ^{2} + 4 )}

\int_{0}^{2} \frac{30 t ^{2}}{4 + t ^{3}} d t

\int \frac{x ^{3} + x}{x + 1} d x

\int sin (5) (t) cos (4) (t) d t

What is the integral of 1-x^2-3x^5 ?
The integral of 1-x^2-3x^5 is x-(x^3)/3-(x^6)/2+C