What is the derivative of 2pir-pir^2 ?

The derivative of 2pir-pir^2 is 2pi-2pir

What is the first derivative of 2pir-pir^2 ?

The first derivative of 2pir-pir^2 is 2pi-2pir

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derivative of

2 π r - π r^{2}

2 π - 2 π r

Solution steps

\frac{d}{d r} (2 π r - π r^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (2 π r) - \frac{d}{d r} (π r^{2})

\frac{d}{d r} (2 π r) = 2 π

\frac{d}{d r} (π r^{2}) = 2 π r

= 2 π - 2 π r

n = 0 \sum \infty (\frac{2 x}{3})^{n}

\int \frac{4 e ^{x}}{e ^{2 x} + 2 e ^{x} + 1} d x

\frac{\partial}{\partial x} (x e^{5 x y})

\int x^{2} (x^{3} + 9)^{\frac{1}{2}} d x

\int \frac{x}{( x ^{2} + 1 ) ^{3}} d x

What is the derivative of 2pir-pir^2 ?
The derivative of 2pir-pir^2 is 2pi-2pir
What is the first derivative of 2pir-pir^2 ?
The first derivative of 2pir-pir^2 is 2pi-2pir