What is the derivative of \sqrt[4]{x^3} ?

The derivative of \sqrt[4]{x^3} is 3/(4x^{1/4)}

What is the first derivative of \sqrt[4]{x^3} ?

The first derivative of \sqrt[4]{x^3} is 3/(4x^{1/4)}

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\frac{3}{4 x ^{\frac{1}{4}}}

Solution steps

Apply the chain rule:

\frac{1}{4 ( x ^{3} ) ^{\frac{3}{4}}} \frac{d}{d x} (x^{3})

= \frac{1}{4 ( x ^{3} ) ^{\frac{3}{4}}} \frac{d}{d x} (x^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{1}{4 ( x ^{3} ) ^{\frac{3}{4}}} \cdot 3 x^{2}

Simplify

\frac{1}{4 ( x ^{3} ) ^{\frac{3}{4}}} \cdot 3 x^{2} : \frac{3}{4 x ^{\frac{1}{4}}}

= \frac{3}{4 x ^{\frac{1}{4}}}

y = \frac{4 x}{x + 2}

\frac{\partial}{\partial x} (e^{s i n (x + c t)})

t \frac{d y}{d t} = t^{3} + 11 t^{3} y

\frac{d}{d x} (lo g_{7} (6 x - 5))

\int (x 1 - x^{2}) d x

What is the derivative of \sqrt[4]{x^3} ?
The derivative of \sqrt[4]{x^3} is 3/(4x^{1/4)}
What is the first derivative of \sqrt[4]{x^3} ?
The first derivative of \sqrt[4]{x^3} is 3/(4x^{1/4)}