What is the derivative of sqrt(3x^2cos(2x)) ?

The derivative of sqrt(3x^2cos(2x)) is (sqrt(3)x(-xsin(2x)+cos(2x)))/(sqrt(cos(2x))\sqrt{x^2)}

What is the first derivative of sqrt(3x^2cos(2x)) ?

The first derivative of sqrt(3x^2cos(2x)) is (sqrt(3)x(-xsin(2x)+cos(2x)))/(sqrt(cos(2x))\sqrt{x^2)}

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derivative of

3 x^{2} cos (2 x)

\frac{3 x ( - x sin ( 2 x ) + cos ( 2 x ) )}{cos ( 2 x ) x ^{2}}

Solution steps

\frac{d}{d x} (3 x^{2} cos (2 x))

Apply the chain rule:

\frac{1}{2 3 x ^{2} cos ( 2 x )} \frac{d}{d x} (3 x^{2} cos (2 x))

= \frac{1}{2 3 x ^{2} cos ( 2 x )} \frac{d}{d x} (3 x^{2} cos (2 x))

\frac{d}{d x} (3 x^{2} cos (2 x)) = 3 (2 x cos (2 x) - 2 x^{2} sin (2 x))

= \frac{1}{2 3 x ^{2} cos ( 2 x )} \cdot 3 (2 x cos (2 x) - 2 x^{2} sin (2 x))

Simplify

\frac{1}{2 3 x ^{2} cos ( 2 x )} \cdot 3 (2 x cos (2 x) - 2 x^{2} sin (2 x)) : \frac{3 x ( - x sin ( 2 x ) + cos ( 2 x ) )}{cos ( 2 x ) x ^{2}}

= \frac{3 x ( - x sin ( 2 x ) + cos ( 2 x ) )}{cos ( 2 x ) x ^{2}}

x \to 7 - lim (\frac{4 x}{x - 7})

\int sin (2 x) cos (2 x) d x

x y^{2} y^{^{'}} = y^{3} - 4 x^{3}

x \to 4 lim (tan (x))

f (x) = 2 x, (32, 8)

What is the derivative of sqrt(3x^2cos(2x)) ?
The derivative of sqrt(3x^2cos(2x)) is (sqrt(3)x(-xsin(2x)+cos(2x)))/(sqrt(cos(2x))\sqrt{x^2)}
What is the first derivative of sqrt(3x^2cos(2x)) ?
The first derivative of sqrt(3x^2cos(2x)) is (sqrt(3)x(-xsin(2x)+cos(2x)))/(sqrt(cos(2x))\sqrt{x^2)}