What is the limit as x approaches 1+of 9/(x^3-1) ?

The limit as x approaches 1+of 9/(x^3-1) is infinity

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limit as x approaches 1+of 9/(x^3-1)

x \to 1 + lim (\frac{9}{x ^{3} - 1})

\infty

Solution steps

x \to 1 + lim (\frac{9}{x ^{3} - 1})

For

x

approaching

1

from the right

, x > 1 \Rightarrow x^{3} - 1 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

- 5 x^{2} + 3 y^{2} = 1

\frac{\partial}{\partial x} (x yz w + 2 x + 3 y + 4 z + w)

\frac{d}{d x} ((\frac{2 x}{x ^{2} + 1})^{2})

\int (6 x) d x

\frac{\partial}{\partial y} (e^{- y} cos (x))

What is the limit as x approaches 1+of 9/(x^3-1) ?
The limit as x approaches 1+of 9/(x^3-1) is infinity