What is the solution for y^{''}+ay+b=0 ?

The solution for y^{''}+ay+b=0 is y=c_{1}cos(sqrt(a)t)+c_{2}sin(sqrt(a)t)-b/a

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y^{''}+ay+b=0

y^{^{''}} + a y + b = 0

y = c_{1} cos (a t) + c_{2} sin (a t) - \frac{b}{a}

Solution steps

y^{''} (t) + a y (t) + b = 0

Solve linear ODE:

y = c_{1} cos (a t) + c_{2} sin (a t) - \frac{b}{a}

y = c_{1} cos (a t) + c_{2} sin (a t) - \frac{b}{a}

\frac{d}{d x} (x y^{2} - y^{3})

n = 1 \sum \infty \frac{sin ( \frac{1}{n} )}{n}

n = 1 \sum \infty 4^{n + 1}

n = 1 \sum \infty \frac{1}{n ^{2} + 6 n}

\int x^{9} e^{x} d x

What is the solution for y^{''}+ay+b=0 ?
The solution for y^{''}+ay+b=0 is y=c_{1}cos(sqrt(a)t)+c_{2}sin(sqrt(a)t)-b/a