What is the derivative of f(x)=sqrt(2-3x) ?

The derivative of f(x)=sqrt(2-3x) is -3/(2sqrt(2-3x))

What is the first derivative of f(x)=sqrt(2-3x) ?

The first derivative of f(x)=sqrt(2-3x) is -3/(2sqrt(2-3x))

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derivative of

f (x) = 2 - 3 x

- \frac{3}{2 2 - 3 x}

Solution steps

\frac{d}{d x} (2 - 3 x)

Apply the chain rule:

\frac{1}{2 2 - 3 x} \frac{d}{d x} (2 - 3 x)

= \frac{1}{2 2 - 3 x} \frac{d}{d x} (2 - 3 x)

\frac{d}{d x} (2 - 3 x) = - 3

= \frac{1}{2 2 - 3 x} (- 3)

Simplify

\frac{1}{2 2 - 3 x} (- 3) : - \frac{3}{2 2 - 3 x}

= - \frac{3}{2 2 - 3 x}

\int - 7 sec^{2} (x) d x

y^{^{'}} + 5 y = 0, y (0) = 2

\int (5 x^{2} - 5 x + 4 tan (x)) d x

\frac{d}{d x} (20 x (2 x^{2} + 7)^{4})

What is the derivative of f(x)=sqrt(2-3x) ?
The derivative of f(x)=sqrt(2-3x) is -3/(2sqrt(2-3x))
What is the first derivative of f(x)=sqrt(2-3x) ?
The first derivative of f(x)=sqrt(2-3x) is -3/(2sqrt(2-3x))