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Popular >

y^'=xe^{x^2-y}

Solution

y^{^{'}} = x e^{x^{2} - y}

Solution

y = ln (\frac{1}{2} e^{x^{2}} + c_{1})

Solution steps

y^{'} (x) = x e^{x^{2} - y}

Solve separable ODE:

y = ln (\frac{1}{2} e^{x^{2}} + c_{1})

y = ln (\frac{1}{2} e^{x^{2}} + c_{1})

Popular Examples

y^'=((3x^6e^{y/x}+x^4y^2))/(x^5y)

y^{^{'}} = \frac{( 3 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2} )}{x ^{5} y}

(dy)/(dt)=t\sqrt[3]{y}

xy^'=y+x^2e^{2x}

x y^{^{'}} = y + x^{2} e^{2 x}

integral from 0 to pi of (sin^2(x))

\int_{0}^{π} (sin^{2} (x)) d x

limit as x approaches 0 of (cos(10x)-1)/(x^2)

x \to 0 lim (\frac{cos ( 10 x ) - 1}{x ^{2}})

Frequently Asked Questions (FAQ)

What is the solution for y^'=xe^{x^2-y} ?
The solution for y^'=xe^{x^2-y} is y=ln(1/2 e^{x^2}+c_{1})