What is the sum from n=0 to infinity of 1/(n+6) ?

The sum from n=0 to infinity of 1/(n+6) is diverges

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sum from n=0 to infinity of 1/(n+6)

n = 0 \sum \infty \frac{1}{n + 6}

diverges

Solution steps

n = 0 \sum \infty \frac{1}{n + 6}

Apply Series Integral Test:

diverges

= diverges

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x})

\int e^{x} cos (4 x) d x

f (x) = x^{4} - 17 x^{2} + 16, at x = - 2

\int sin^{2} (x) cos (6 x) d x

\frac{- 5}{x ^{6}}

What is the sum from n=0 to infinity of 1/(n+6) ?
The sum from n=0 to infinity of 1/(n+6) is diverges