What is the solution for y^'=(3x^6e^{y/x}+x^4y^2)/(x^5y) ?

The solution for y^'=(3x^6e^{y/x}+x^4y^2)/(x^5y) is y=-\W((3ln(x)+c_{1})/e)x-x

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y^'=(3x^6e^{y/x}+x^4y^2)/(x^5y)

y^{^{'}} = \frac{3 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2}}{x ^{5} y}

y = - W (\frac{3 ln ( x ) + c _{1}}{e}) x - x

Solution steps

y^{'} (x) = \frac{3 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2}}{x ^{5} y}

Solve using substitution:

y = - W (\frac{3 ln ( x ) + c _{1}}{e}) x - x

y = - W (\frac{3 ln ( x ) + c _{1}}{e}) x - x

\frac{d}{d x} ((x + 1)^{\frac{1}{2}})

\int ln^{5} (x) d x

x \to 10 + lim (\frac{1}{( x - 10 ) ^{2}})

\int_{- 5}^{5} (x - 25 - x^{2}) d x

\frac{d}{d x} (\frac{1}{3 + ( 2 x + 1 ) ^{2}})

What is the solution for y^'=(3x^6e^{y/x}+x^4y^2)/(x^5y) ?
The solution for y^'=(3x^6e^{y/x}+x^4y^2)/(x^5y) is y=-\W((3ln(x)+c_{1})/e)x-x