What is the tangent of f(x)=2sqrt(x),(1,2) ?

The tangent of f(x)=2sqrt(x),(1,2) is y=x+1

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tangent of f(x)=2sqrt(x),(1,2)

tangent of

f (x) = 2 x, (1, 2)

y = x + 1

Solution steps

Find the slope of

f (x) = 2 x : \frac{df ( x )}{d x} = \frac{1}{x}

Compute the slope of

f (x) = 2 x

(1, 2) : m = 1

Find the line with slope m=

1

and passing through

(1, 2) : y = x + 1

y = x + 1

\int \frac{4}{x ( x - 4 ) ^{2}} d x

x \to 1 + lim (arcsin (x))

\frac{d}{d x} (ln (ln (ln (2 x))))

\frac{d}{d x} (x^{3} + y)

x \to \infty lim (x \cdot e^{x})

What is the tangent of f(x)=2sqrt(x),(1,2) ?
The tangent of f(x)=2sqrt(x),(1,2) is y=x+1