What is the derivative of-sin(2x+1) ?

The derivative of-sin(2x+1) is -2cos(2x)

What is the first derivative of-sin(2x+1) ?

The first derivative of-sin(2x+1) is -2cos(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- sin (2 x) + 1)

- 2 cos (2 x)

Solution steps

\frac{d}{d x} (- sin (2 x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (sin (2 x)) + \frac{d}{d x} (1)

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

\frac{d}{d x} (1) = 0

= - cos (2 x) \cdot 2 + 0

Simplify

= - 2 cos (2 x)

\frac{d}{d x} ((5 x - 3) (4 x - \frac{3}{x}))

\int \frac{x ^{3}}{x ^{4} - 8} d x

\int \frac{x ^{2}}{x ^{3} + 9} d x

\frac{d}{d x} ((a x^{2} + b x + c) e^{\frac{- x}{4}})

\frac{s ^{1}}{s ( s ^{2} + s + 1 )}

What is the derivative of-sin(2x+1) ?
The derivative of-sin(2x+1) is -2cos(2x)
What is the first derivative of-sin(2x+1) ?
The first derivative of-sin(2x+1) is -2cos(2x)