What is the sum from n=1 to infinity of 1/(n^{1/2)} ?

The sum from n=1 to infinity of 1/(n^{1/2)} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 1/(n^{1/2)}

n = 1 \sum \infty \frac{1}{n ^{\frac{1}{2}}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{\frac{1}{2}}}

Apply p-Series Test:

diverges

= diverges

y = 12 cos (2) (x)

\int \frac{3 x}{x ^{2} + 5} d x

4 y^{^{'}} + t y = 3

\int x^{5} e^{2 x} d x

\int csc^{2} (5 x) d x

What is the sum from n=1 to infinity of 1/(n^{1/2)} ?
The sum from n=1 to infinity of 1/(n^{1/2)} is diverges